Oracle
DB<>Fiddle:自定義類型和函式 (ORA-24344)
我製作了Oracle 的 GetVertices() 函式的自定義版本。該解決方案涉及創建使用者定義的類型和函式。
這是程式碼(工作):
CREATE TYPE vertex_type_cust AS object ( x NUMBER, y NUMBER, z NUMBER, w NUMBER, id NUMBER ); CREATE TYPE vertex_set_type_cust AS TABLE OF vertex_type_cust; CREATE OR replace FUNCTION getvertices_cust(geometry mdsys.sdo_geometry) RETURN vertex_set_type_cust IS i NUMBER; dims NUMBER; coords NUMBER; result vertex_set_type_cust; dim mdsys.sdo_dim_array; is_zero BOOLEAN; etype NUMBER; BEGIN result := vertex_set_type_cust(); -- handle the POINT case here IF (geometry.sdo_ordinates IS NULL) THEN result.extend; result(1) := vertex_type_cust(geometry.sdo_point.x, geometry.sdo_point.y, geometry.sdo_point.z,NULL,1); RETURN result; END IF; -- all other cases here coords := geometry.sdo_ordinates.count; dims := geometry.get_dims; IF (dims = 0) THEN RETURN result; END IF; coords := coords/dims; FOR i IN 0 .. coords-1 LOOP result.extend; IF (dims = 2) THEN result(i+1) := vertex_type_cust(geometry.sdo_ordinates(2*i+1), geometry.sdo_ordinates(2*i+2), NULL,NULL,i+1); ELSIF (dims = 3) THEN result(i+1) := vertex_type_cust(geometry.sdo_ordinates(3*i+1), geometry.sdo_ordinates(3*i+2), geometry.sdo_ordinates(3*i+3) ,NULL,i+1); ELSIF (dims = 4) THEN result(i+1) := vertex_type_cust(geometry.sdo_ordinates(4*i+1), geometry.sdo_ordinates(4*i+2), geometry.sdo_ordinates(4*i+3), geometry.sdo_ordinates(4*i+4), i+1); END IF; END LOOP; RETURN result; END;
測試數據:
create table a_sdo_geometry_tbl (line_id integer, shape mdsys.sdo_geometry); insert into a_sdo_geometry_tbl (line_id, shape) values (1, sdo_geometry (2002, null, null, sdo_elem_info_array (1,2,1), sdo_ordinate_array (671539.6852734378,4863324.181436138, 671595.0500703361,4863343.166556185, 671614.013553706,4863350.343483042, 671622.2044153381,4863353.525396131)) ); insert into a_sdo_geometry_tbl (line_id, shape) values (2, sdo_geometry (2002, null, null, sdo_elem_info_array (1,2,1), sdo_ordinate_array (71534.5567096211,4863119.991809748, 671640.7384688659,4863157.132745253, 671684.8621150404,4863172.022995591)) ); insert into a_sdo_geometry_tbl (line_id, shape) values (3, sdo_geometry (2002, null, null, sdo_elem_info_array (1,2,1), sdo_ordinate_array (671622.2044153381,4863353.525396131, 671633.3267164109,4863357.846229106, 671904.0614077691,4863451.286166754)) ); insert into a_sdo_geometry_tbl (line_id, shape) values (4, sdo_geometry (2002, null, null, sdo_elem_info_array (1,2,1), sdo_ordinate_array (671684.8620521119,4863172.022995591, 671892.1496144319,4863244.141440067, 671951.2156571196,4863264.824310392, 671957.4471461186,4863266.847617676, 671966.8243856924,4863269.146632658)) ) select a.line_id, b.id as vertex_id, b.x, b.y from a_sdo_geometry_tbl a cross join table(getvertices_cust(a.shape)) b --<<-- the query uses the custom function order by a.line_id, b.id;
問題:
我正在使用線上 Oracle 環境測試此解決方案,因為我在公司的 Oracle 數據庫中沒有 CREATE TYPE 權限。
當我在 Oracle 的免費測試環境 (19c) 中執行上面的程式碼時,我可以讓它工作:
- https://livesql.oracle.com/
- 創建功能:截圖
- 使用函式查詢:截圖
但是,當我嘗試使用db<>fiddle執行程式碼時,在創建函式時出現錯誤:
- db<>fiddle session (18c)
ORA-24344: success with compilation error
問題:
使用 db<>fiddle 創建自定義函式時,如何避免出現該錯誤?
我知道 Oracle Live 和 db<>fiddle(19c 與 18c)之間存在版本差異。但如果這是問題所在,我會感到驚訝。這對我來說似乎不是版本問題。
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在函式定義之後添加一個。https://dbfiddle.uk/?rdbms=oracle_18&fiddle=4031e203694674dbc764b5290dd93bdb