Select
使用組中的值選擇同一組中的所有值
我有以下查詢:
SELECT SubstitutionGroupID, Material.Number, Material.DescriptionEN FROM MaterialSubstitution INNER JOIN Material on Material.MaterialID = MaterialSubstitution.MaterialID ORDER BY SubstitutionGroupID, Material.Number
結果範例:
SubstitutionGroupID Number DescriptionEN 52494 303H603021 HINGE R 52494 3H603020 HINGE R 52495 303H604031 TRAY EJECT 52495 3H604030 TRAY EJECT (1/2)
我想要一個查詢,我可以在其中定義一個數字並在一個 SubstitutionGroupID 中接收所有數字。
如果我了解您的要求,我相信這就是您所追求的:
DECLARE @Number NVARCHAR(30); SET @Number = '3H603020'; SELECT ms.SubstitutionGroupID, subs.Number, subs.DescriptionEN FROM MaterialSubstitution AS ms INNER JOIN Material AS m ON m.MaterialID = ms.MaterialID INNER JOIN Material AS subs ON subs.MaterialID = ms.MaterialID WHERE m.Number = @Number ORDER BY ms.SubstitutionGroupID, subs.Number
您需要
Material
再次加入以找到給定的“替換”(因此是別名subs
)Material.Number